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Artificial Crowd Noise

psuflyguy

psuflyguy

Well-Known Member
Mar 23, 2013
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It’s been strange watching football games where artificial noise has replaced actual crowd noise. A few that I saw had artificial crowd noise that sounded like the ocean in a conch shell.
Just for fun, what do you think each B1G venue will pump through the speakers at wrestling matches? For instance, I’m thinking Carver Hawkeye plays a non-stop track of thousands of people chanting “Stalling!” What say you?
 
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If they are going to do it, they need to actually have somebody operating the system to emphasize a pin or points. I love the NLWC events but the way they did the artificial noise at the last event where it just seemed to me like the same noise on a loop was total garbage and I actually muted the audio, including the announcers as part of that, because I couldn't take the background.

Basically, I feel if you are not going to do it right then don't even do it at all which I am completely fine with.
 
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nerfstate said:
I’m telling you, audio from the world cup in Tehran (where DT pinned Yazdani) is where it’s at.
Click to expand...

That was awesome. Say what you will about
the Iranian government, they have the best fans in the world. And they even cheered for Taylor.

I remember watching a Champions League soccer game in the early 2000s. Held in Istanbul. Standing room only crowd, chanting, jumping up and down. You could see the pre-stressed concrete supports for the upper deck flexing under the strain. Those people must have been on some uppers, because they were going hard before the game even started and never let up. Never seen anything like that.
 
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AndEEss said:
That was awesome. Say what you will about
the Iranian government, they have the best fans in the world. And they even cheered for Taylor.

I remember watching a Champions League soccer game in the early 2000s. Held in Istanbul. Standing room only crowd, chanting, jumping up and down. You could see the pre-stressed concrete supports for the upper deck flexing under the strain. Those people must have been on some uppers, because they were going hard before the game even started and never let up. Never seen anything like that.
Click to expand...
Yeah, I'm not in the habit of praising Iran, but their wrestling fans act the way I wish ours did. Passion for great wrestling. Do you think these folks roll their eyes when someone yells too much at a match?
 
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AndEEss said:
... the Iranian ... best fans in the world ... soccer game ... in Istanbul ... jumping up and down. You could see the pre-stressed concrete supports for the upper deck flexing under the strain ...
Click to expand...

So Iranian fans invaded Istanbul to stomp down the stands? That’s cool! I wonder whether they were jumping rhythmically, for maximum chance of going-out-with-a-bang success. 🧐
EasygoingConsiderateDassie-max-1mb.gif
 
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AndEEss said:
That was awesome. Say what you will about
the Iranian government, they have the best fans in the world. And they even cheered for Taylor.

I remember watching a Champions League soccer game in the early 2000s. Held in Istanbul. Standing room only crowd, chanting, jumping up and down. You could see the pre-stressed concrete supports for the upper deck flexing under the strain. Those people must have been on some uppers, because they were going hard before the game even started and never let up. Never seen anything like that.
Click to expand...
You've never been to a tOSU or Michigan White Out game?
 
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82bordeaux said:
You've never been to a tOSU or Michigan White Out game?
Click to expand...

I’m going to let you guys in on a secret. My dad was roommates with Jack Ham and various other malcontents and ne’er-do-wells of that era.

I went to Illinois for undergrad and Virginia Tech for grad school. I was the one kid in the student section cheering for PSU when they came to Champaign for football or wrestling. I’ve never been to a PSU home game. Only been on campus a couple of times.

That said, the architectural integrity of Beaver Stadium never seems to be in question during a white out. The aura of danger during a soccer game in far Eastern Europe, complete with burning road flares and smoke bombs, and Jurassic Park style fences to keep fans off the field and apart from each other, is something else.
 
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AndEEss said:
I’m going to let you guys in on a secret. My dad was roommates with Jack Ham and various other malcontents and ne’er-do-wells of that era.

I went to Illinois for undergrad and Virginia Tech for grad school. I was the one kid in the student section cheering for PSU when they came to Champaign for football or wrestling. I’ve never been to a PSU home game. Only been on campus a couple of times.

That said, the architectural integrity of Beaver Stadium never seems to be in question during a white out. The aura of danger during a soccer game in far Eastern Europe, complete with burning road flares and smoke bombs, and Jurassic Park style fences to keep fans off the field and apart from each other, is something else.
Click to expand...

there was at least a question back in 2006

www.collegian.psu.edu

Zombie song will fade out

The bouncing associated with the popular football tune has raised concerns.During last year's Ohio State game, the techno rhythm known as "Zombie Nation" hit the airwaves at Beaver Stadium nine
www.collegian.psu.edu www.collegian.psu.edu
 
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danoftw said:
The ref telling Casey to shut up will be loud and clear. Maryland will blast Ficker through a giant stack of concert speakers
Click to expand...
I was going to say Maryland have silence with a braying donkey mixed in.
 
STAND with PRIDE said:
The DeCantgo doll Gif makes up for the inexcusable doubling up of the shaky bridge gif earlier, Marcia.
Click to expand...
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
 
82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...
So tempted to report this ;)
 
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82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...
giphy.gif
 
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82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...
giphy.gif
 
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82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...
Just today my son thats in the 7th grade asked me for some help on an extra credit math question he had. I thought it was a word scramble that had numbers thrown in it. ;) Thank goodness mom was home to help him out with it.
Your post was a bad flashback to this afternoon.
I'm such a knuckle dragger. 😔
 
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82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...

Im calling BS.
 
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82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...

Is that like the torque of the pork+the angle of the dangle......oh hell I cant remember the rest let alone where I was during calc.
 
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AndEEss said:
That said, the architectural integrity of Beaver Stadium never seems to be in question during a white out. The aura of danger during a soccer game in far Eastern Europe, complete with burning road flares and smoke bombs, and Jurassic Park style fences to keep fans off the field and apart from each other, is something else.
Click to expand...
At Maracanã stadium in Rio Brazil the field is surrounded by a dry moat. The players refs enter through a tunnel that runs from the locker rooms to the field side of the moat. Fans on the upper decks used giant sparklers winch rain sparks on the decks below and some make hot air balloons by igniting oily rags in tin cans suspended below a paper bag.
 
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GLCoast said:
At Maracanã stadium in Rio Brazil the field is surrounded by a dry moat. The players refs enter through a tunnel that runs from the locker rooms to the field side of the moat. Fans on the upper decks used giant sparklers winch rain sparks on the decks below and some make hot air balloons by igniting oily rags in tin cans suspended below a paper bag.
Click to expand...
giphy.gif
 
Honestly, for me, the crowd noise thing doesn’t matter, though I wonder how the wrestlers feel about it.
 
I find the crowd noise on my TV to bee too loud. I have a hard time understanding the announcers. If I could turn the crowd noise down 20-30% I would be happy. As it is.......I have a hard time following certain announcers because the crowd noise is drowning them out......Especially those that trail off at the end. GGGGrrrr
PS: Pretty much exclusively football is what I an talking about
 
Last edited:
82bordeaux said:
It's the Tacoma Narrows Bridge. Didn't you take calculus in High School? It's easily explained here...

Mathematically, the force generated from such cable-like springs have the form

if d>0, then Fs = - k d, and if d<0, then Fs=0.
where k is the spring constant and d is the displacement from equilibrium of the spring.

The kinetic energy consists of two parts, the kinetic energy of vertical motion

(m/2) (dy/dt)2
and the kinetic energy of the torsional motion, which turns out to be

(m/6) L2 (dx/dt)2
where L is the beam length.

Similarly the potential energy has two parts, -mgy the potential energy of the vertical displacement, and the potential energy due to torsional rotation angle x,

(K/2) [ ( y - (L/2) sin x )+ + ( y + (L/2) sin x )+ ]2
where the ( )+ means it contributes only if the term is positive, i.e. it accounts for the cable-like springs.

The equation of motion is derived by minimizing the total energy L = T - V, i.e. we differentiate the energy with respect to time and set the result equal to zero. Then a small viscous dissipation term is added and if the springs never lose tension, the resulting equation for the torsional motion is <

x'' + c x' + k sin(x) cos(x) = f(t)
and for the vertical motion is

y'' + c y' + (k/3) y = g.

Got it?
Click to expand...
Now do the equations describing the resonant instability of TnT.
 
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