OT Question for today

[sluggo72]

Question #9 (Math)
Question #9: Model: P=2,320(1.2)x
The model is used to estimate the deer population in a region, where x is the number of years after the year 2009. Using the model, estimate the deer population in the year 2018.

Answer choices:

- A. 9,976
- B. 11,971
- C. 25,056
- D. 14,365
for 10 bonus points show your work.

 

[LionJim]

Question #9 (Math)
Question #9: Model: P=2,320(1.2)x
The model is used to estimate the deer population in a region, where x is the number of years after the year 2009. Using the model, estimate the deer population in the year 2018.

Answer choices:

- A. 9,976
- B. 11,971
- C. 25,056
- D. 14,365
for 10 bonus points show your work.

This is a linear function. Since mathematical models for population are exponential functions (which allow us, for example, to estimate the population ten years previous) the correct answer is none of the above.

 

[sluggo72]

This is a linear function. Since mathematical models for population are exponential functions (which allow us, for example, to estimate the population ten years previous) the correct answer is none of the above.

if none of the above is the answer, then which of the given would you choose?

 

[UncleLar]

This is a linear function. Since mathematical models for population are exponential functions (which allow us, for example, to estimate the population ten years previous) the correct answer is none of the above.

Disagree. The question that was asked has nothing at all to do with the validity of the model. The correct answer is c.

2,320 times 1.2 equals 2,784
x = 2018 - 2009 = 9
9 times 2,784 = 25,056

 

[artsandletters]

This is a linear function. Since mathematical models for population are exponential functions (which allow us, for example, to estimate the population ten years previous) the correct answer is none of the above.

Another math question:

What do you get when you subtract 47 from 90?

 

[LionJim]

If x=9 then 1.2x equals around 11 so the answer is obvious.

 

[LionJim]

Disagree. The question that was asked has nothing at all to do with the validity of the model. The correct answer is c.

2,320 times 1.2 equals 2,784
x = 2018 - 2009 = 9
9 times 2,784 = 25,056

Of course, but one would hope that students don’t actually see such a problem worded like that. The way the appropriate model works is so fascinating that it would be a crying shame to miss that opportunity to illuminate.

 

[CentexLion]

Question #9 (Math)
Question #9: Model: P=2,320(1.2)x
The model is used to estimate the deer population in a region, where x is the number of years after the year 2009. Using the model, estimate the deer population in the year 2018.

Answer choices:

- A. 9,976
- B. 11,971
- C. 25,056
- D. 14,365
for 10 bonus points show your work.

Answer: More info needed.

The model predicts that at the end of 2017 (x = 8), that the population will be 22,272
The model predicts that at the end of 2018 (x = 9), that the population will be 25,056

The Question is "estimate the deer population in the year 2018", so in that case, X could be any number from X = 8 to X =9. If you wanted Midnight of June 30, then the model predicts X = 8.5 or a population of 23,664 (none of the choices)

 

[sluggo72]

Disagree. The question that was asked has nothing at all to do with the validity of the model. The correct answer is c.

2,320 times 1.2 equals 2,784
x = 2018 - 2009 = 9
9 times 2,784 = 25,056

Well at 10 am or so you would have been wrong. The answer they gave was 11,971, and for the live of me, I could not get that answer. (plug it in, you should get a whole number for the answer and that doesnt). So I was going nuts with, what did I miss?
Well it appears they have changed their answer since this morning , and you are correct, now, but for a while I thought, what the heck am I missing here (I got that as well)

updated....
Answer #9
Question #9: Model: P=2,320(1.2)x
The model is used to estimate the deer population in a region, where x is the number of years after the year 2009. Using the model, estimate the deer population in the year 2018.

- Answer: C. 25,056

https://www.msn.com/en-us/money/edu...-you-get-right/ss-AAEhygx?li=BBnb7Kz#image=18

 

[sluggo72]

Of course, but one would hope that students don’t actually see such a problem worded like that. The way the appropriate model works is so fascinating that it would be a crying shame to miss that opportunity to illuminate.

well see this....
https://www.msn.com/en-us/money/edu...-you-get-right/ss-AAEhygx?li=BBnb7Kz#image=18

and BTW they have changed their answer from 11971 to 25,056. I could not figure how they got 11971, so I came here to see what the heck I did wrong.

 

[Op2]

If you assume 20% growth (because of 1.2) per year and assume that for 9 years then you get 1.2 ^ 9 = 5.16. And if you multiply that by the starting number of 2,320 you get 11,971. In fact, that's what I initially did. I now see that reading the question more literally you get 25,056. But regardless, I don't really like how the question is worded. Maybe I'm overthinking it.

 

[sluggo72]

If you assume 20% growth (because of 1.2) per year and assume that for 9 years then you get 1.2 ^ 9 = 5.16. And if you multiply that by the starting number of 2,320 you get 11,971. In fact, that's what I initially did. I now see that reading the question more literally you get 25,056. But regardless, I don't really like how the question is worded. Maybe I'm overthinking it.

maybe the x was suppose to be superscript, but did not come out like that in print. As mentioned, what you got, was the correct answer at 10 am, it has now been changed.

 

[Ct. Lion]

Is this an actual formula the Pa. Game Commission is using? If so, are they saying in nine years the deer population in one defined deer region jumped from 2,320 to 25,056? That would be unlikely even if they abandoned deer hunting of all kinds. Fawn predation by bears, bobcats, coyotes, cars, adverse weather, etc. would insure that that kind of increase would never happen.
But we do still have hunting and though they have cut back some on the doe permits, there are still plenty of does, fawns and button bucks being shot off every year on doe tags making these kind of estimated population increases improbable.
This kind of deer population growth certainly hasn't occurred in the Allegheny National Forest where I have been hunting since 1978 - 2018. Anyway, maybe it is just a hypothetical math question.

 

[sluggo72]

Is this an actual formula the Pa. Game Commission is using? If so, are they saying in nine years the deer population in one defined deer region jumped from 2,320 to 25,056? That would be unlikely even if they abandoned deer hunting of all kinds. Fawn predation by bears, bobcats, coyotes, cars, adverse weather, etc. would insure that that kind of increase would never happen.
But we do still have hunting and though they have cut back some on the doe permits, there are still plenty of does, fawns and button bucks being shot off every year on doe tags making these kind of estimated population increases improbable.
This kind of deer population growth certainly hasn't occurred in the Allegheny National Forest where I have been hunting since 1978 - 2018. Anyway, maybe it is just a hypothetical math question.

no it was a question from a GED test, pretty sure they just made up the stuff about deer to fit a mathematical equation.

 

[Ct. Lion]

Thanks Sluggo,

 

[psuro]

Now figure out the answer to this question....

If Jim Harbaugh recruits two high school quarterbacks a year for 4 years, what is the probability that an incoming freshman will be the starting quarterback as a senior?

 

[sluggo72]

Now figure out the answer to this question....

If Jim Harbaugh recruits two high school quarterbacks a year for 4 years, what is the probability that an incoming freshman will be the starting quarterback as a senior?

0

 

[psuro]

0

Show your work for full credit.

 

[Langmuir]

It is a terrible model as written since in 2009 it says the deer population is 0. It should be P=2320 *1.2^x. Then it makes sense.

 

[sluggo72]

Show your work for full credit.

easy it the cross product of the following...


cross




naught x naught is naught. QED

 

[BobPSU92]

Show your work for full credit.

jim harbaugh is an overrated asshole.

0

 

[phillybillyreprise]

They said that there would be no math.

 

[BobPSU92]

They said that there would be no math.

None of what these guys are talking about is real. They’re making up MATHS. to look smart.

 

[LionJim]

well see this....
https://www.msn.com/en-us/money/edu...-you-get-right/ss-AAEhygx?li=BBnb7Kz#image=18

and BTW they have changed their answer from 11971 to 25,056. I could not figure how they got 11971, so I came here to see what the heck I did wrong.

Ah, I understand now.

 

[sluggo72]

They said that there would be no math.

No GD!! They said know math!!!

 

[step.eng69]

 

[Ct. Lion]

Step, Mandelbrot says hello.